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Product investigation using titration explained

Syllabus VMBO: Product investigation

Calculate content from a reference factor and compare like quantities.

The reference connects volume and mass

For this fictional method, 1.00 mL of titrant corresponds to 0.0500 g of the acid being measured. This factor applies only to the stated method and substance. No mole conversion is needed here.

Compare matching units

A label in g per 100 mL must be compared with a result in g per 100 mL. This is not automatically a mass percentage. For a diluted sample, also use the dilution factor. An indicator endpoint is not automatically pH 7.

Worked example

10.0 mL of product uses 12.0 mL of titrant. The reference is 0.0500 g acid per mL of titrant.

  1. Acid in the sample: 12.0 × 0.0500 = 0.600 g.
  2. Scale from 10.0 mL to 100 mL: multiply by 10.

The measured content is 6.00 g per 100 mL.